Buyela esikolweni. root Ngaphezu

iikhompyutha Kule mihla yanamhlanje elektroniki yokubala ingcambu ka'B inani ayikho umsebenzi onzima. Umzekelo, √2704 = 52, lo wena ubale nayiphi sokubala. Ngethamsanqa, lo wokubala kuphela kwi Windows, kodwa kwi eziqhelekileyo, nkqu kakhulu nabalulamileyo, ifowuni. Yinyani ukuba ngequbuliso (amathuba ephantsi, intelekelelo apho, koko, iquka ukongeza lweengcambu), uya kufumana ngokwakho ngaphandle kwemali ekhoyo, ke, yeha, kufuneka sithembele ubuchopho babo.

Uqeqesho lo inqondo balifake. Ngokukodwa abo bangengabo ngokufuthi usebenza namanani, kwaye nangakumbi oko iingcambu. Ukudibanisa nokuthabatha na iingcambu - Amazing elungileyo ingqondo isithukuthezi. Kwaye ndiza kukubonisa step by Ukongeza inyathelo ezingcanjini. Nkulumo Imizekelo ukuze ngolu hlobo.

Inxaki ekufuneka lula:

√2 + 3√48-4 × √27 + √128

Oku kubonisa ngqiqweni. Ukwenzela ukuba kube lula kuyimfuneko ukuba zazise bonke radicands kwifom jikelele. Thina step ngenyathelo:

Inani lokuqala ayikwazi lula. Siphendu- kwikota yesibini.

3√48 ukubola kwi multipliers 48: 48 = 2 × 24 okanye 48 × 16 = 3. Ingcambu ka 24 akuyona inombolo, ngamanye ngentsalela fraction. Ekubeni sifuna ixabiso ngqo, iingcambu omalunga ayifanelekanga. Ingcambu ka 16 amane, ukuba ukuphuma phantsi uphawu ingcambu. Thina ukufumana 4 × 3 × √3 = × 12 √3

Le ngxelo ilandelayo kuthi lelikhabayo, oko kukuthi, sibhalwe thabatha -4 x √ (27.) Gcobisa 27 multipliers. Thina ukufumana 27 × 3 = 9. Asazi ukusebenzisa multipliers iqhezu ngenxa amaqhezu ukubala ingcambu ye zakhiwo. 9 baphuma phantsi plate, ngamanye Thina ubale ingcambu. Thina ukufumana athi ilandelayo: -4 × 3 × √3 = -12 × √3

kota izayo √128 ukubala inxalenye anokuthatyathwa baphuma phantsi ingcambu. 128 = 64 × 2, apho √64 = 8. Ukuba uyakucinga kuya kuba lula le nkulumo ngokuthi: √128 = √ (8 ^ 2 × 2)

Senza ubhale amazwi lula ngokweekota:

√2 + 12 × √3-12 × √3 + 8 × √2

Ngoku dibanisa inani radicals efanayo. Awukwazi ukudibanisa okanye ukuthabatha amazwi radicals ezahlukeneyo. root Ukudibanisa ufuna ukuthobela lo mthetho.

Sifumana impendulo ilandelayo:

√2 + 12√3-12√3 + 8√2 = 9√2

√2 = 1 × √2 - Ndiyathemba ukuba algebra wagqiba ashiye izinto ezinjalo abayi kuba iindaba kuwe.

Amabinzana angamelwa nje kuphela ingcambu, kodwa kwakhona nge ingcambu cubic okanye n-zehydrochloric elithile.

Ukudibanisa nokuthabatha iingcambu kunye izalathi ezahlukeneyo, kodwa radicand ezilingana, ngulo ulandelayo:

Ukuba une ibinzana ezifana √a + ∛b + ∜b, asinokwazi ukuyicazulula lento binzana ngolu hlobo lulandelayo:

∛b + ∜b = 12 × √b4 + 12 × √b3

12√b4 + 12 × √b3 = 12 × √b4 + B3

Sayibuyisela amalungu ezimbini ukuya salathisi oqhelekileyo nengcambu. Apha siye sasebenzisa iingcambu kulo propati, apho ifundeka ngolu hlobo lulandelayo: ukuba inani izidanga yokuthetha ezinkulu kunye nenani index ingcambu liphindaphindwe ngenani elifanayo, lisenza izibalo zalo kuhlala ingatshintshanga.

Qaphela: izalathi dibanisa i kuphela xa iphinda phindiweyo.

Makhe senze umzekelo apho akhoyo phantsi iqhezu.

5√8-4 × √ (1/4) + √72-4 × √2

Siza isigqibo amanyathelo:

5√8 = 5 * 2√2 - esizenzayo engcanjini le ibuyiseke.

- 4√ (1/4) = - 4 √1 / (√4) = - 4 * 1/2 = - 2

Ukuba ingcambu umzimba imelwe iqhezu, iqhezu asiyiyo inxalenye yale tshintsho, ukuba ingcambu ka'B tivi kunye, umahluli. Ngenxa yoko, siye abafumene ukulingana echazwe apha ngasentla.

√72-4√2 = √ (2 × 36) - 4√2 = 2√2

10√2 + 2√2-2 = 12√2-2

Ngoko ukuze ufumane impendulo.

Eyona nto ibalulekileyo ukuze ukhumbule ukuba amanani akhabayo ngeke betekisi ingcambu ngesifundo exponent. Ukuba radicand nokuba idigri negative, ngoko ke binzana unsolvable.

Ukudibanisa iingcambu kunokwenzeka kuphela xa kuqondana amabinzana kwi radicals ngenxa yokuba efanayo. Kukwasebenza kwanjalo kuyo umahluko.

Ukudibanisa lweengcambu yamanani kunye izalathi ezahlukeneyo ezenziwa wayezizuzisa ubungakanani lilonke engcanjini zombini. Lo mthetho imiphumela iyafana nje zinganyantswa zifana xa ukudibanisa okanye nokuthabatha amaqhezu.

Ukuba radicand kukho inani elinebaxiweyo i sine ye eli binzana lula ngokuthi zithathe ukuba ingcambu phakathi index kunye nobungakanani kukho zifana.